To deliver 0.5 lb of nitrogen from urea (46-0-0), how much urea is needed?

To calculate the amount of urea needed to deliver 0.5 lbs of nitrogen, it’s essential to understand the composition of urea, which is a fertilizer with the formulation of 46-0-0. This indicates that urea contains 46% nitrogen by weight.

To find out how much urea is required to provide 0.5 lbs of nitrogen, you can set up the calculation based on the percentage of nitrogen in urea. Since urea is 46% nitrogen, you would divide the desired amount of nitrogen (0.5 lbs) by the percentage of nitrogen in urea (expressed as a decimal).

Here’s the calculation:

• Desired nitrogen = 0.5 lbs

• Percentage of nitrogen in urea = 46/100 = 0.46

So, the amount of urea needed can be calculated as follows:

Amount of urea needed = Desired nitrogen / Percentage of nitrogen in urea

Amount of urea needed = 0.5 lbs / 0.46 = approximately 1.08 lbs.

This result indicates that you would need approximately 1.08 lbs of urea to deliver 0.5 lbs of nitrogen. Thus, option B is the